前言:
现在姐妹们对“fabs c语言”大体比较珍视,你们都需要剖析一些“fabs c语言”的相关文章。那么小编也在网摘上网罗了一些有关“fabs c语言””的相关知识,希望咱们能喜欢,小伙伴们快快来学习一下吧!我们曾在《用 C 语言画光(一):基础》中,使用到带符号距离场(signed distance field, SDF)表示圆形:
SDF 的梯度(gradient)代表 SDF 变化最大的方向,可用这个方向去决定用哪一个字符。
我们通过差分求 SDF 的梯度近似值,然后用 atan2() 求出梯度的角度:
用 C 语言简单实现,在
画布中画一个半径 0.8 并带有 0.1 寛度外框的圆形:
#include <math.h>#include <stdio.h>#define T doubleT f(T x, T y) { return sqrt(x * x + y * y) - 0.8f;}char outline(T x, T y) { T delta = 0.001; if (fabs(f(x, y)) < 0.05) { T dx = f(x + delta, y) - f(x - delta, y); T dy = f(x, y + delta) - f(x, y - delta); return "|/=\\|/=\\|"[(int)((atan2(dy, dx) / 6.2831853072 + 0.5) * 8 + 0.5)]; } else if (f(x, y) < 0) return '.'; else return ' ';}int main() { for (T y = -1; y < 1; y += 0.05, putchar('\n')) for (T x = -1; x < 1; x += 0.025) putchar(outline(x, y));}
然后,我们就可以画多个圆形,把它们适当地旋转和缩放,用构造实体几何比它们组合起来,那么用19行代码就可以画出小猪佩奇了:
// ASCII Peppa Pig by Milo Yip#include <math.h>#include <stdio.h>#include <stdlib.h>#define T doubleT c(T x,T y,T r){return sqrt(x*x+y*y)-r;}T u(T x,T y,T t){return x*cos(t)+y*sin(t);}T v(T x,T y,T t){return y*cos(t)-x*sin(t);}T fa(T x,T y){return fmin(c(x,y,0.5),c(x*0.47+0.15,y+0.25,0.3));}T no(T x,T y){return c(x*1.2+0.97,y+0.25,0.2);}T nh(T x,T y){return fmin(c(x+0.9,y+0.25,0.03),c(x+0.75,y+0.25,0.03));}T ea(T x,T y){return fmin(c(x*1.7+0.3,y+0.7,0.15),c(u(x,y,0.25)*1.7,v(x,y,0.25)+0.65,0.15));}T ey(T x,T y){return fmin(c(x+0.4,y+0.35,0.1),c(x+0.15,y+0.35,0.1));}T pu(T x,T y){return fmin(c(x+0.38,y+0.33,0.03),c(x+0.13,y+0.33,0.03));}T fr(T x,T y){return c(x*1.1-0.3,y+0.1,0.15);}T mo(T x,T y){return fmax(c(x+0.15,y-0.05,0.2),-c(x+0.15,y,0.25));}T o(T x,T y,T(*f)(T,T),T i){T r=f(x,y);return fabs(r)<0.02?(atan2(f(x,y+1e-3)-r,f(x+1e-3,y)-r)+0.3)*1.273+6.5:r<0?i:0;}T s(T x,T y,T(*f)(T,T),T i){return f(x,y)<0?i:0;}T f(T x,T y){return o(x,y,no,1)?fmax(o(x,y,no,1),s(x,y,nh,12)):fmax(o(x,y,fa,1),fmax(o(x,y,ey,11),fmax(o(x,y,ea,1),fmax(o(x,y,mo,1),fmax(s(x,y,fr,13),s(x,y,pu,12))))));}int main(int a,char**b){for(T y=-1,s=a>1?strtod(b[1],0):1;y<0.6;y+=0.05/s,putchar('\n'))for(T x=-1;x<0.6;x+=0.025/s)putchar(" .|/=\\|/=\\| @!"[(int)f(u(x,y,0.3),v(x,y,0.3))]);}
2倍:
4 倍:
8 倍:
今天也是精致的猪猪女孩~
文章转载至知乎
学习从来不是一个人的事情,要有个相互监督的伙伴,工作需要学习C/C++或者为了入行、转行学习C/C++的伙伴可以私信回复小编“学习”领取全套免费C/C++学习资料、视频
版权声明:
本站文章均来自互联网搜集,如有侵犯您的权益,请联系我们删除,谢谢。
标签: #fabs c语言