龙空技术网

js的递归函数

孤帆月下 97

前言:

现时大家对“js递归循环”可能比较重视,你们都想要分析一些“js递归循环”的相关文章。那么小编也在网摘上网罗了一些关于“js递归循环””的相关内容,希望我们能喜欢,你们快快来学习一下吧!

视频加载中...

//ajax获取post后端数据

function ajxpostdata(business, url, Npeople) {

let data = {}

if (Npeople == "undefined") {

data = {

businessname: business,

}

} else {

data = {

businessname: business,

Npeoplename: Npeople

}

}

let ajxpostdata = new XMLHttpRequest();

ajxpostdata.open('POST', url, true);

ajxpostdata.onreadystatechange = function () {

if (ajxpostdata.readyState == 4) {

if (ajxpostdata.status == 200) {

if (JSON.parse(ajxpostdata.responseText)['data1']) {

obtain(JSON.parse(ajxpostdata.responseText)['data1']);

}

AA.numberofpeople(JSON.parse(ajxpostdata.responseText)['data']);

}

}

}

ajxpostdata.send(JSON.stringify(data));

}

//递归函数

function obtain() {

if (document.getElementById('select02') && document.getElementById('div02')) {

document.getElementById('select02').remove();

document.getElementById('div02').remove();

}

let url = ';;

let arr01 = [];

let arr02 = [];

let arr05 = [];

let content = (Array.prototype.shift.apply(arguments));

let arr = ['同意', '拒绝'];

for (let i = 0; i < content.length; i++) {

let num = Math.floor(Math.random() * 2)

content[i]['confirm'] = arr[num];

arr01.push(content[i]);

}

for (let i = 0; i < arr01.length; i++) {

if (arr01[i]['confirm'] == '拒绝') {

arr02.push(arr01[i]['id']);

arr05.push(arr01[i])

} else {

arr06.push(arr01[i])

}

}

let number = arr02.length;

if (arr02.length == 0) {

return

} else {

ajxpostdata(number, url, arr05);

}

contentdisplay()

}

标签: #js递归循环