前言:
眼前各位老铁们对“python实现a算法八数码”可能比较注重,你们都想要了解一些“python实现a算法八数码”的相关资讯。那么小编同时在网络上搜集了一些有关“python实现a算法八数码””的相关内容,希望我们能喜欢,我们快快来学习一下吧!初学Python,试着将以前在树莓派上用C语言写的程序改成了Python版本的。四位共阴数码管与树莓派的电路连接方式如下:
a ~ p ------------------------------ GPIO0 ~ GPIO7
d1 ~ d4----------------------------- GPIO11 ~ GPIO8
下面是电路连接好之后的照片:
连接好电路之后写程序,程序代码如下:
#!/usr/bin/env python
import RPi.GPIO as GPIO
import time
BIT0 = 3
BIT1 = 5
BIT2 = 24
BIT3 = 26
segCode = [0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f] #0~9
pins = [11,12,13,15,16,18,22,7,3,5,24,26]
bits = [BIT0, BIT1, BIT2, BIT3]
def print_msg():
print 'Program is running...'
print 'Please press Ctrl+C end the program...'
def digitalWriteByte(val):
GPIO.output(11, val & (0x01 << 0))
GPIO.output(12, val & (0x01 << 1))
GPIO.output(13, val & (0x01 << 2))
GPIO.output(15, val & (0x01 << 3))
GPIO.output(16, val & (0x01 << 4))
GPIO.output(18, val & (0x01 << 5))
GPIO.output(22, val & (0x01 << 6))
GPIO.output(7, val & (0x01 << 7))
def display_1():
GPIO.output(BIT0, GPIO.LOW)
for i in range(10):
digitalWriteByte(segCode[i])
time.sleep(0.5)
def display_2():
for bit in bits:
GPIO.output(bit, GPIO.LOW)
for i in range(10):
digitalWriteByte(segCode[i])
time.sleep(0.5)
def display_3(num):
b0 = num % 10
b1 = num % 100 / 10
b2 = num % 1000 / 100
b3 = num / 1000
if num < 10:
GPIO.output(BIT0, GPIO.LOW)
GPIO.output(BIT1, GPIO.HIGH)
GPIO.output(BIT2, GPIO.HIGH)
GPIO.output(BIT3, GPIO.HIGH)
digitalWriteByte(segCode[b0])
elif num >= 10 and num < 100:
GPIO.output(BIT0, GPIO.LOW)
digitalWriteByte(segCode[b0])
time.sleep(0.002)
GPIO.output(BIT0, GPIO.HIGH)
GPIO.output(BIT1, GPIO.LOW)
digitalWriteByte(segCode[b1])
time.sleep(0.002)
GPIO.output(BIT1, GPIO.HIGH)
elif num >= 100 and num < 1000:
GPIO.output(BIT0, GPIO.LOW)
digitalWriteByte(segCode[b0])
time.sleep(0.002)
GPIO.output(BIT0, GPIO.HIGH)
GPIO.output(BIT1, GPIO.LOW)
digitalWriteByte(segCode[b1])
time.sleep(0.002)
GPIO.output(BIT1, GPIO.HIGH)
GPIO.output(BIT2, GPIO.LOW)
digitalWriteByte(segCode[b2])
time.sleep(0.002)
GPIO.output(BIT2, GPIO.HIGH)
elif num >= 1000 and num < 10000:
GPIO.output(BIT0, GPIO.LOW)
digitalWriteByte(segCode[b0])
time.sleep(0.002)
GPIO.output(BIT0, GPIO.HIGH)
GPIO.output(BIT1, GPIO.LOW)
digitalWriteByte(segCode[b1])
time.sleep(0.002)
GPIO.output(BIT1, GPIO.HIGH)
GPIO.output(BIT2, GPIO.LOW)
digitalWriteByte(segCode[b2])
time.sleep(0.002)
GPIO.output(BIT2, GPIO.HIGH)
GPIO.output(BIT3, GPIO.LOW)
digitalWriteByte(segCode[b3])
time.sleep(0.002)
GPIO.output(BIT3, GPIO.HIGH)
else:
print 'Out of range, num should be 0~9999 !'
def setup():
GPIO.setmode(GPIO.BOARD) #Number GPIOs by its physical location
for pin in pins:
GPIO.setup(pin, GPIO.OUT) #set all pins' mode is output
GPIO.output(pin, GPIO.HIGH) #set all pins are high level(3.3V)
def loop():
while True:
print_msg()
display_1()
time.sleep(1)
display_2()
time.sleep(1)
tmp = int(raw_input('Please input a num(0~9999):'))
for i in range(500):
display_3(tmp)
time.sleep(1)
def destroy(): #When program ending, the function is executed.
for pin in pins:
GPIO.output(pin, GPIO.LOW) #set all pins are low level(0V)
GPIO.setup(pin, GPIO.IN) #set all pins' mode is input
if __name__ == '__main__': #Program starting from here
setup()
try:
loop()
except KeyboardInterrupt:
destroy()
标签: #python实现a算法八数码